Mrs Dunn managed to save R50 000 as part of R80 000 deposit for a new ci Her parents are willing to give her a loan of R30 000 to be paid back with interest at the end of 12 months at \( 8,4 \% \) p.a interest compounded quarterly. Use the information above to answer the following questions. 4.3.1 Calculate the quarterly interest rate. 4.3.2 Manually calculate the total amount of money she will be owing her parents by the third quarter. 4.3.3 Calculate the difference in the total amount paid to the parents if the parents charged Mrs Dunn \( 8,4 \% \) per annum simple interest on the loan. 4.3 .4 Mrs Dunn further invests R12 000 in a bank which offers her the following interest rates: 6,25\% interest compounded yearly for the first year and an interest rate of 6,95\% compounded yearly for the second year. Calculate the total interest that Mrs Dunn's investment would earn at the end of the second year.
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To calculate the quarterly interest rate, simply divide the annual interest rate by the number of compounding periods per year. So, \( 8.4\% \div 4 = 2.1\% \) per quarter. This means Mrs Dunn can expect her loan to increase by this percentage every three months! To find out how much she’ll owe her parents by the third quarter, we use the formula for compound interest: \( A = P(1 + r/n)^{nt} \). Here, \( P \) is the loan amount (R30,000), \( r \) is the annual interest rate (0.084), \( n \) is the number of times interest is compounded per year (4), and \( t \) is the number of years (0.75 for three quarters). The amount owed becomes approximately R30,000(1 + 0.021)^{3} which calculates to roughly R30,000(1.0649), equating to about R31,947. For simple interest, the formula is \( A = P(1 + rt) \). Here, \( r \) is still the annual interest rate (0.084), \( t \) is 1 year, and \( P \) is R30,000. So, \( A = 30,000(1 + 0.084 \cdot 1) = R32,520 \). The difference between the amounts (compounded vs. simple) is about R31,947 - R32,520 = -R573. If Mrs. Dunn’s parents had chosen the simple route, she would have paid more. For her investment, we first calculate the interest for the first year at \( 6.25\% \): \( I_1 = 12,000 \times 0.0625 = R750 \). The total in the bank after the first year is \( R12,750 \). For the second year, at \( 6.95\% \), we use the total from year one: \( I_2 = 12,750 \times 0.0695 \approx R886.25 \). Therefore, Mrs. Dunn's total interest earned at the end of the second year is \( R750 + R886.25 = R1,636.25 \). What a savvy way to grow her initial investment!