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Chapter Test \( \mathbf{B} \) (continued) 8 \( \begin{array}{l}\text { 9. A scientist needs } \frac{7}{12} \text { liter of sulfuric acid to perform an experiment. She has } \\ \frac{11}{12} \text { liter of nitric acid. She has } \frac{5}{6} \text { liter more nitric acid than sulfuric acid. Can she } \\ \text { perform the experiment? }\end{array} \)

Ask by Vaughan Frank. in the United States
Jan 24,2025

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Answer

La científica **no puede realizar el experimento** porque solo tiene \( \frac{1}{12} \) litro de ácido sulfúrico, pero necesita \( \frac{7}{12} \) litro.

Solution

No, la científica **no puede realizar el experimento** debido a que no tiene suficiente ácido sulfúrico. A continuación, se detalla el razonamiento paso a paso: 1. **Datos conocidos:** - **Cantidad necesaria de ácido sulfúrico:** \( \frac{7}{12} \) litro. - **Cantidad de ácido nítrico disponible:** \( \frac{11}{12} \) litro. - **Relación entre ácido nítrico y ácido sulfúrico:** Tiene \( \frac{5}{6} \) litro más de ácido nítrico que de ácido sulfúrico. 2. **Definamos las variables:** - Sea \( S \) la cantidad de ácido sulfúrico que posee la científica. 3. **Establecemos la relación entre los ácidos:** \[ \text{Cantidad de ácido nítrico} = S + \frac{5}{6} \] 4. **Sustituimos la cantidad de ácido nítrico disponible:** \[ S + \frac{5}{6} = \frac{11}{12} \] 5. **Resolviendo para \( S \):** \[ S = \frac{11}{12} - \frac{5}{6} = \frac{11}{12} - \frac{10}{12} = \frac{1}{12} \text{ litro} \] 6. **Comparación con la cantidad necesaria:** - **Cantidad necesaria:** \( \frac{7}{12} \) litro. - **Cantidad disponible:** \( \frac{1}{12} \) litro. 7. **Conclusión:** \[ \frac{1}{12} < \frac{7}{12} \] La científica solo posee \( \frac{1}{12} \) litro de ácido sulfúrico, lo cual es **insuficiente** para realizar el experimento que requiere \( \frac{7}{12} \) litro.

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To determine if the scientist can perform her experiment, we first need to assess how much nitric acid she has. The scientist requires \(\frac{7}{12}\) liter of sulfuric acid. Since she has \(\frac{5}{6}\) liter more nitric acid than sulfuric acid, we convert \(\frac{5}{6}\) to have a common denominator with \(\frac{7}{12}\). The fraction \(\frac{5}{6}\) is equivalent to \(\frac{10}{12}\). Therefore, the amount of nitric acid she has is \(\frac{7}{12} + \frac{10}{12} = \frac{17}{12}\) liters. Since \(\frac{17}{12}\) liters of nitric acid is greater than \(\frac{11}{12}\) liters (the quantity she has), she indeed has enough nitric acid to proceed with her experiment!

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