37. $$ 5^{\circ} \mathrm{Cda} $$ to yintirilgan 405 g eritmada necha gramm ammonly xlorid boladi. Bu tuzning shu haroratdagi eruvchanlik koeffisiyenti 35 g ga teng. A) 35 B) 105 C) 70 D) 100 38. 50 g to'yingan eritmada $$ 40^{\circ} \mathrm{Cda} 6,5 \mathrm{~g} $$ kaliy sulfat bo’adi. Eruvchanlik koeflisiyentini aniqlang. A) 13 B) 14,9 C) 10 D) 38 39. 200 g eritmada $$ 50^{\circ} \mathrm{C} d a 54 \mathrm{~g} $$ natriy xlorid bo'ladi. Tuzning eruvchanligini aniqlang. A) 9,18 B) 37 C) 27 D) 23 40. Natriy xloridning $$ 10^{\circ} \mathrm{Cdagi} $$ to'yingan 200 g eritmasini quriguncha bug'latish yoli bilan $$ 52,6 \mathrm{~g} $$ tuz olindi. Natriy xloridning $$ 10^{\circ} \mathrm{Cdagi} $$ eruvchanligini aniqlang. A) 35,7 B) 201.25 C) 37,6 D)23,5 41. $$ 60^{\circ} \mathrm{C} $$ dagi NaCl ning 620 g to'yingan eritmasi $$ 40^{\circ} \mathrm{C} $$ gacha sovutilganda necha $$ g $$ tuz cho'kmaga tushadi? $$ S\left(60^{\circ} \mathrm{C}\right)=55 S\left(40^{\circ} \mathrm{C}\right)=40 \mathrm{~g} $$ A) 60 B)70 C) 125 D) 97,5 42. Natriy nitritning $$ 10^{\circ} \mathrm{Cdagi} $$ eruvchanligi $$ 80,5 \mathrm{~g} $$ ga teng. Shu haroratda 250 g suvda necha gramm tuzni eritish mumkín. A) 35,7 B) 201,25 C) 37,6 D) 23,5

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Quyidagi savollarga toʻgʻri javoblar quyidagicha:

**37.** Javob: **B) 105**

**38.** Javob: **B) 14,9**

**39.** Javob: **B) 37**

**40.** Javob: **A) 35,7**

**41.** Javob: **A) 60**

**42.** Javob: **B) 201,25**

Har bir savolning echimini qisqacha ko'rib chiqamiz:

**37.**
- To'yingan eritma massasi = 405 g
- Eruvchanlik koeffisiyenti = 35 g/100 g suv
- Suv massasi $$ W = \frac{405}{1 + 0.35} = 300 $$ g
- Tuz massasi $$ S = 0.35 	imes 300 = 105 $$ g

**38.**
- Eritma massasi = 50 g
- Tuz massasi = 6,5 g
- Suv massasi = 43,5 g
- Eruvchanlik koeffisiyenti $$ S = \frac{6,5}{43,5} 	imes 100 \approx 14,9 $$ g/100 g suv

**39.**
- Eritma massasi = 200 g
- Tuz massasi = 54 g
- Suv massasi = 146 g
- Eruvchanlik koeffisiyenti $$ S = \frac{54}{146} 	imes 100 \approx 37 $$ g/100 g suv

**40.**
- Eritma massasi = 200 g
- Tuz massasi = 52,6 g
- Suv massasi = 147,4 g
- Eruvchanlik koeffisiyenti $$ S = \frac{52,6}{147,4} 	imes 100 \approx 35,7 $$ g/100 g suv

**41.**
- 60°C dagi eritma massasi = 620 g
- Eruvchanlik koeffisiyentlari: $$ S(60°C) = 55 $$ g/100 g suv, $$ S(40°C) = 40 $$ g/100 g suv
- Suv massasi $$ W = \frac{620}{1 + 0.55} = 400 $$ g
- 60°C dagi tuz massasi = 55% × 400 = 220 g
- 40°C dagi eruvchanligi = 40% × 400 = 160 g
- Cho'kmaga tushadigan tuz = 220 - 160 = 60 g

**42.**
- Eruvchanlik koeffisiyentlari: $$ S = 80,5 $$ g/100 g suv
- Suv massasi = 250 g
- Eritilishi mumkin bo'lgan tuz massasi $$ = 80,5 	imes 2,5 = 201,25 $$ g

Agar qo'shimcha savollar bo'lsa yoki izoh kerak boʻlsa, bemalol so'rashingiz mumkin!
**Javoblar:** 37. **B) 105** 38. **B) 14,9** 39. **B) 37** 40. **A) 35,7** 41. **A) 60** 42. **B) 201,25**

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