Question
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(1) \( \frac{1}{2 x}\left(6 x^{2}-8 x\right)= \) (2) \( \frac{1}{3 x}\left(6 x^{2}-9 x\right)= \) (3) \( \frac{1}{a}\left(3 a^{2}-5 a\right)= \) (4) \( \frac{1}{2 a}\left(2 a^{2}-6 a\right)= \) (5) \( \frac{1}{2 a}\left(6 a^{2}-2 a\right)= \) (6) \( \frac{1}{3 x}\left(6 x^{3}-3 x\right)= \) (7) \( \frac{1}{2 x}\left(8 x^{3}-12 x^{2}+6 x\right)= \)

Ask by Colon Dickson. in Brazil
Feb 03,2025

Real Tutor Solution

Tutor-Verified Answer

Answer

1. \( \frac{1}{2x}(6x^{2} - 8x) = 3x - 4 \) 2. \( \frac{1}{3x}(6x^{2} - 9x) = 2x - 3 \) 3. \( \frac{1}{a}(3a^{2} - 5a) = 3a - 5 \) 4. \( \frac{1}{2a}(2a^{2} - 6a) = a - 3 \) 5. \( \frac{1}{2a}(6a^{2} - 2a) = 3a - 1 \) 6. \( \frac{1}{3x}(6x^{3} - 3x) = 2x^{2} - 1 \) 7. \( \frac{1}{2x}(8x^{3} - 12x^{2} + 6x) = 4x^{2} - 6x + 3 \)

Solution

Claro, aqui estão as simplificações das expressões fornecidas: 1. \[ \frac{1}{2x}(6x^{2} - 8x) = 3x - 4 \] 2. \[ \frac{1}{3x}(6x^{2} - 9x) = 2x - 3 \] 3. \[ \frac{1}{a}(3a^{2} - 5a) = 3a - 5 \] 4. \[ \frac{1}{2a}(2a^{2} - 6a) = a - 3 \] 5. \[ \frac{1}{2a}(6a^{2} - 2a) = 3a - 1 \] 6. \[ \frac{1}{3x}(6x^{3} - 3x) = 2x^{2} - 1 \] 7. \[ \frac{1}{2x}(8x^{3} - 12x^{2} + 6x) = 4x^{2} - 6x + 3 \]

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Mind Expander

Let's have some fun with algebra and determinants! Simplifying each expression will give us a clearer, more compact form. For (1): \( \frac{1}{2 x}(6 x^{2}-8 x) = \frac{3}{x}(x - \frac{4}{3}) = 3 - \frac{4}{2}\) simplifies beautifully. For (2): \( \frac{1}{3 x}(6 x^{2}-9 x) = \frac{2}{x}(2x - 3) = 2\cdot(2 - 3/x)\), making math feel like a summer breeze! Seeing the patterns here, common mistakes often arise when distributing fractions incorrectly. Remember to apply the distributive property cautiously and consolidate your terms; it can save you from a messy outcome! If you're eager for more mathematical inspirations, consider diving broad into algebraic identities or polynomials; they unveil secrets that can turn any mathematical puzzle into a piece of cake!

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