\( 28+4 y-z=32 \) \( 2 x+14 y+4 z=35 \) \( x+3 y+\operatorname{coz}=24 \) From

To solve this system of equations, you might want to start with the first equation: \( 28 + 4y - z = 32 \). Rearranging gives you \( z = 4y - 4 \). Next, substitute \( z \) into the other equations to simplify them. When you tackle the second equation \( 2x + 14y + 4z = 35 \) with the value of \( z \) substituted, you can reduce the number of variables and work towards finding values for \( x \), \( y \), and \( z \). Remember that isolating a variable in one equation can really help illuminate the relationships between them! Additionally, always watch out for arithmetic mishaps! One common mistake is not balancing the equations after substituting a variable. Keep your calculations tidy! A small error can snowball into a big problem later, so double-check your work as you go along.