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A fair six-sided dice is rolled three times. What is the probability that the outcome of
the first roll is lower than the outcomes of the second and third roll?

Ask by Matthews Young. in the United Arab Emirates
Jan 16,2025

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The probability is .

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To find the probability that the outcome of the first roll is lower than the outcomes of the second and third rolls, we can analyze the scenarios. Let’s denote the results of the three rolls as R1, R2, and R3.
  1. There are a total of possible outcomes when rolling the die three times, since each die has 6 faces.
  2. The condition we want to satisfy is R1 < R2 and R1 < R3. For any specific value of R1 (from 1 to 6), the corresponding number of valid outcomes for R2 and R3 can be computed:
    • If R1 = 1, then R2 and R3 can be 2, 3, 4, 5, or 6 (5 options each, yielding combinations).
    • If R1 = 2, then R2 and R3 can be 3, 4, 5, or 6 (4 options each, yielding combinations).
    • If R1 = 3, then R2 and R3 can be 4, 5, or 6 (3 options each, yielding combinations).
    • If R1 = 4, then R2 and R3 can be 5 or 6 (2 options each, yielding combinations).
    • If R1 = 5, then R2 and R3 can only be 6 (1 option each, yielding combination).
    • If R1 = 6, there are no valid outcomes for R2 and R3, yielding combinations.
Now, summing all the successful outcomes gives:
Thus, the probability that R1 is lower than both R2 and R3 is:
So the final answer is or approximately 25.46%.

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