Graph the line that contains the point \( (4,0) \) and has a slope of \( -\frac{2}{3} \).

To graph the line that contains the point \( (4,0) \) with a slope of \( -\frac{2}{3} \), you can use the slope-intercept form of a line, \( y = mx + b \), where \( m \) is the slope and \( b \) is the y-intercept. Starting from the point \( (4,0) \), move down 2 units (since the slope is negative) and to the right 3 units. This movement leads you to the point \( (7, -2) \). Plot these two points and draw the line through them, extending in both directions. For extra points, remember that you can identify additional points on this line using the slope. From any point, a rise of \(-2\) (down) and a run of \(3\) (right) will land you another point on the line. Another common approach is to determine the intercepts where the line crosses the axes, which further anchors your graph nicely!