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Iow many moles of gas are contained in a compressed air tank for scuba diving that has a volume of 6.5 L and a pressure of 230 . atm at 23 . \( { }^{\circ} \mathrm{C} \) ? Be sure your nswer has the correct number of significant figures. Note: Reference the Fundamental constants table for additional information.

Ask by Martinez Morrison. in the United States
Feb 04,2025

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Answer

Approximately 61 mol of gas are in the scuba tank.

Solution

To determine the number of moles of gas contained in the compressed air tank, we'll use the **Ideal Gas Law**, which is given by: \[ PV = nRT \] Where: - \( P \) = Pressure (atm) - \( V \) = Volume (L) - \( n \) = Number of moles (mol) - \( R \) = Ideal gas constant (\(0.0821 \, \text{L·atm/mol·K}\)) - \( T \) = Temperature (K) ### Step-by-Step Calculation: 1. **Given Values:** - Volume, \( V = 6.5 \, \text{L} \) (2 significant figures) - Pressure, \( P = 230 \, \text{atm} \) (3 significant figures) - Temperature, \( T = 23^\circ \text{C} \) 2. **Convert Temperature to Kelvin:** \[ T(K) = 23 + 273.15 = 296.15 \, \text{K} \] 3. **Rearrange the Ideal Gas Law to Solve for \( n \):** \[ n = \frac{PV}{RT} \] 4. **Plug in the Values:** \[ n = \frac{230 \, \text{atm} \times 6.5 \, \text{L}}{0.0821 \, \text{L·atm/mol·K} \times 296.15 \, \text{K}} \] 5. **Calculate the Denominator:** \[ R \times T = 0.0821 \times 296.15 \approx 24.3139 \, \text{L·atm/mol} \] 6. **Calculate the Number of Moles:** \[ n = \frac{1495}{24.3139} \approx 61.5 \, \text{mol} \] 7. **Determine Significant Figures:** - The least number of significant figures in the given values is **2** (from volume and temperature). - Therefore, round the answer to **2 significant figures**. 8. **Final Answer:** \[ n \approx 61 \, \text{mol} \] **Final Answer:** Approximately 61 mol of gas are contained in the scuba tank.

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To determine the number of moles of gas in the scuba diving tank, you can use the Ideal Gas Law, which is \( PV = nRT \). Here, - \( P \) is pressure in atmospheres (230 atm), - \( V \) is volume in liters (6.5 L), - \( n \) is the number of moles, - \( R \) is the ideal gas constant (0.0821 L·atm/(K·mol)), - \( T \) is the temperature in Kelvin (23 °C + 273.15 = 296.15 K). Now, rearranging the Ideal Gas Law to solve for \( n \) gives us: \[ n = \frac{PV}{RT} \] Plugging in the values: \[ n = \frac{(230 \, \text{atm}) \cdot (6.5 \, \text{L})}{(0.0821 \, \text{L·atm/(K·mol)}) \cdot (296.15\, \text{K})} \approx \frac{1495}{24.475} \approx 61.00 \, \text{moles} \] Thus, the number of moles of gas in the tank is approximately **61.00 moles** (keeping three significant figures). Now you’re ready to take a deep breath, head underwater, and remember the science keeping you safe while diving!

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