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Use the properties of exponents to determine whether the pair of expressions are equivalent. \[ \left(\frac{1}{3}\right)^{4} \text { and }\left(\frac{1}{9}\right)^{2} \] The expressions \( \square \) equal. The expression \( \left(\frac{1}{3}\right)^{4} \) can be rewritten as 3 \( \square \) The expression \( \left(\frac{1}{9}\right)^{2} \) can be rewritten as 9 \( \square \) , which is equal to 3 \( \square \) The expressions have the same base, \( \square \) equal. (Type integers or simplified fractions.)

Ask by Simpson Christensen. in the United States
Jan 23,2025

Real Tutor Solution

Tutor-Verified Answer

Answer

The expressions \(\left(\frac{1}{3}\right)^{4}\) and \(\left(\frac{1}{9}\right)^{2}\) are equal. Both simplify to \(\frac{1}{81}\).

Solution

To determine whether the expressions \(\left(\frac{1}{3}\right)^{4}\) and \(\left(\frac{1}{9}\right)^{2}\) are equivalent, we will simplify both expressions step by step. 1. **Simplifying \(\left(\frac{1}{3}\right)^{4}\)**: \[ \left(\frac{1}{3}\right)^{4} = \frac{1^{4}}{3^{4}} = \frac{1}{81} \] 2. **Simplifying \(\left(\frac{1}{9}\right)^{2}\)**: \[ \left(\frac{1}{9}\right)^{2} = \frac{1^{2}}{9^{2}} = \frac{1}{81} \] Now we can compare the two simplified expressions: - \(\left(\frac{1}{3}\right)^{4} = \frac{1}{81}\) - \(\left(\frac{1}{9}\right)^{2} = \frac{1}{81}\) Since both expressions are equal to \(\frac{1}{81}\), we conclude that: - The expressions \(\left(\frac{1}{3}\right)^{4}\) and \(\left(\frac{1}{9}\right)^{2}\) are equivalent. Now, filling in the blanks: - The expressions \( \text{are} \) equal. - The expression \( \left(\frac{1}{3}\right)^{4} \) can be rewritten as \( \frac{1}{81} \). - The expression \( \left(\frac{1}{9}\right)^{2} \) can be rewritten as \( \frac{1}{81} \), which is equal to \( \frac{1}{81} \). - The expressions have the same base, \( \text{are} \) equal.

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The expressions \( \left(\frac{1}{3}\right)^{4} \) and \( \left(\frac{1}{9}\right)^{2} \) can both be simplified using the properties of exponents. First, let's rewrite \( \left(\frac{1}{3}\right)^{4} \): this becomes \( \frac{1^4}{3^4} = \frac{1}{81} \). Now, for \( \left(\frac{1}{9}\right)^{2} \): here, \( 9\) can be expressed as \( 3^2 \), thus \( \left(\frac{1}{9}\right)^{2} = \left(\frac{1}{3^2}\right)^{2} = \frac{1^2}{3^{2 \times 2}} = \frac{1}{3^4} = \frac{1}{81} \). Thus, both \( \left(\frac{1}{3}\right)^{4} \) and \( \left(\frac{1}{9}\right)^{2} \) evaluate to \( \frac{1}{81} \), so the expressions are indeed \( \square \) equal. In conclusion, we can fill in the blanks as follows: - The expression \( \left(\frac{1}{3}\right)^{4} \) can be rewritten as \( \frac{1}{81} \). - The expression \( \left(\frac{1}{9}\right)^{2} \) can be rewritten as \( \frac{1}{81} \). - Both expressions have been shown to be equal; hence, \( \square \) equal.

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