Question
A 0.171 kg screwdriver initially at rest
slides down a ramp that is inclined
at
.
What is the magnitude of the normal
force of the screwdriver?
slides down a ramp that is inclined
at
What is the magnitude of the normal
force of the screwdriver?
Ask by Savage Davies. in the United States
Mar 22,2025
Upstudy AI Solution
Tutor-Verified Answer
Answer
The normal force of the screwdriver is approximately 0.974 N.
Solution
To find the magnitude of the normal force of the screwdriver, we need to consider the forces acting on the screwdriver as it slides down the ramp.
Given:
- Mass of the screwdriver,
- Angle of inclination of the ramp,
The forces acting on the screwdriver are:
- Weight of the screwdriver,
- Normal force,
- Frictional force,
Since the screwdriver is initially at rest, the net force acting on it is zero. Therefore, the sum of the forces in the horizontal direction is zero, and the sum of the forces in the vertical direction is also zero.
Let’s denote the horizontal component of the weight as
and the vertical component of the weight as
.
The horizontal component of the weight is given by:
The vertical component of the weight is given by:
Since the screwdriver is at rest, the net force in the horizontal direction is zero, which means the normal force is equal to the horizontal component of the weight:
Now, we can calculate the magnitude of the normal force using the given values.
The magnitude of the normal force of the screwdriver is approximately 0.97396 N.
The magnitude of the normal force of the screwdriver is approximately 0.97396 N.
Answered by UpStudy AI and reviewed by a Professional Tutor
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Extra Insights
To find the normal force acting on the screwdriver, we can use the angle of inclination and the weight of the screwdriver. The weight
can be calculated using the formula
, where
and
.
Calculating the weight:
The normal force
is equal to the component of the weight perpendicular to the ramp. This is found using the cosine of the angle:
Thus, the magnitude of the normal force of the screwdriver is approximately: