$$ \begin{aligned} ext { a) } \quad \sin x & =0 \ 0 & \leqslant x \ 0 & \leqslant x \ 0 & \leqslant 360^{\circ}\end{aligned} $$

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$$ \begin{aligned} 	ext { a) } \quad \sin x & =0 \ 0 & \leqslant x \ 0 & \leqslant x \ 0 & \leqslant 360^{\circ}\end{aligned} $$

UpStudy AI · Accepted Answer

To solve the equation $$ \sin x = 0 $$ within the interval $$ 0 \leq x \leq 360^\circ $$, we need to find the angles where the sine function equals zero.

The sine function is equal to zero at the following angles:

$$
x = 0^\circ, 180^\circ, 360^\circ
$$

Thus, the solutions to the equation $$ \sin x = 0 $$ in the specified interval are:

$$
x = 0^\circ, 180^\circ, 360^\circ
$$
The solutions are $$ x = 0^\circ, 180^\circ, 360^\circ $$.

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