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\( \begin{aligned} \text { a) } \quad \sin x & =0 \\ 0 & \leqslant x \\ 0 & \leqslant x \\ 0 & \leqslant 360^{\circ}\end{aligned} \)

Ask by Pope Ruiz. in Canada
Nov 14,2024

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Answer

The solutions are \( x = 0^\circ, 180^\circ, 360^\circ \).

Solution

To solve the equation \( \sin x = 0 \) within the interval \( 0 \leq x \leq 360^\circ \), we need to find the angles where the sine function equals zero. The sine function is equal to zero at the following angles: \[ x = 0^\circ, 180^\circ, 360^\circ \] Thus, the solutions to the equation \( \sin x = 0 \) in the specified interval are: \[ x = 0^\circ, 180^\circ, 360^\circ \]

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Bonus Knowledge

The equation \( \sin x = 0 \) is satisfied at specific angles where the sine function crosses the x-axis. In the interval \( 0 \leq x \leq 360^\circ \), this occurs at \( x = 0^\circ \), \( 180^\circ \), and \( 360^\circ \). These angles indicate the points where the corresponding y-values of the sine function are zero. In practical terms, knowing where \( \sin x = 0 \) is essential in various fields such as engineering and physics, especially in analyzing wave functions and oscillations. For instance, these angles can help determine the moments when a pendulum is at rest at its equilibrium positions, playing a crucial role in designing mechanisms and understanding motion in real-world applications.

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