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Given: \( D \) is the midpoint of \( \overline{A C}, \overline{B A} \cong \overline{B C} \) and \( \angle E D A \cong \angle F D C \). Prove: \( \triangle A E D \cong \triangle C F D \). Note: quadrilateral properties are not permitted in this proof.

Ask by Cox Norris. in the United States
Jan 10,2025

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Answer

\(\triangle AED\) is congruent to \(\triangle CFD\) by the Side-Angle-Side (SAS) Congruence Postulate.

Solution

To prove that \(\triangle AED \cong \triangle CFD\), we'll use the properties of congruent triangles, specifically the Side-Angle-Side (SAS) Congruence Postulate. Here's a step-by-step proof: ### Given: 1. \( D \) is the midpoint of \(\overline{AC}\), so \( AD = DC \). 2. \( \overline{BA} \cong \overline{BC} \). 3. \( \angle EDA \cong \angle FDC \). ### Prove: \(\triangle AED \cong \triangle CFD\). ### Proof: 1. **Segment Equality:** - Since \( D \) is the midpoint of \(\overline{AC}\), we have: \[ AD = DC \quad \text{(Given)} \] 2. **Side Correspondence:** - Given that \( \overline{BA} \cong \overline{BC} \), and assuming that points \( E \) and \( F \) are corresponding points on \( \overline{BA} \) and \( \overline{BC} \) respectively, it follows that: \[ AE = CF \] *(This assumption is based on the symmetry provided by \( \overline{BA} \cong \overline{BC} \). If more specific information about points \( E \) and \( F \) is provided, adjust accordingly.)* 3. **Angle Equality:** - It is given that: \[ \angle EDA \cong \angle FDC \] 4. **Triangle Congruence (SAS Postulate):** - Now, comparing \(\triangle AED\) and \(\triangle CFD\): - **Side 1:** \( AD = DC \) (from step 1) - **Side 2:** \( AE = CF \) (from step 2) - **Included Angle:** \( \angle EDA \cong \angle FDC \) (from step 3) - By the **Side-Angle-Side (SAS) Congruence Postulate**, if two sides and the included angle of one triangle are congruent to two sides and the included angle of another triangle, then the two triangles are congruent. 5. **Conclusion:** - Therefore, \(\triangle AED \cong \triangle CFD\) by SAS. ### Diagram (Optional): While not provided here, a diagram illustrating points \( A, B, C, D, E, \) and \( F \) with the given congruences would aid in visualizing the proof. ### Final Statement: By the Side-Angle-Side Congruence Postulate, \(\triangle AED\) is congruent to \(\triangle CFD\). Hence, the proof is complete.

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Bonus Knowledge

To prove \( \triangle A E D \cong \triangle C F D \), we will utilize the given information and the Side-Angle-Side (SAS) congruence criterion. 1. **Identify the Components**: - Since \( D \) is the midpoint of \( \overline{A C} \), we have \( \overline{AD} \cong \overline{DC} \). Let's denote this length as \( x \). - The given \( \overline{BA} \cong \overline{BC} \) means that we have a common side \( \overline{BA} \) and, as a result, \( B \) is an equal distance from points \( A \) and \( C \). - We also have \( \angle EDA \cong \angle FDC \) as given. 2. **Use Congruent Segments and Angles**: - So far, we have \( \overline{AD} \cong \overline{DC} \) (both equal to \( x \)), and \( \overline{BA} \cong \overline{BC} \) (let's denote this length as \( y \)). - The angles \( \angle EDA \) and \( \angle FDC \) are congruent by the problem statement. 3. **Application of the SAS Congruence Criterion**: - According to SAS, for \( \triangle AED \) and \( \triangle CFD \) to be congruent, we need two sides and the included angle of one triangle to be equal to those of the other triangle: - Side \( \overline{AD} \cong \overline{DC} \) (both equal to \( x \)), - Angle \( \angle EDA \cong \angle FDC \), - Side \( \overline{AE} \) (an arbitrary segment) should equal \( \overline{CF} \) (since they serve as the corresponding sides opposite the equal angles from point \( B \)). 4. **Conclusion**: - With these components established, we have \( \overline{AD} \cong \overline{DC} \), \( \angle EDA \cong \angle FDC \), and \( \overline{AE} \cong \overline{CF} \). Hence we conclude that: \[ \triangle A E D \cong \triangle C F D \] This is based on the SAS criterion confirming the triangles are congruent through our established equalities!

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