Question
Given:
is the midpoint of
and
.
Prove:
.
Note: quadrilateral properties are not permitted in this proof.
Prove:
Note: quadrilateral properties are not permitted in this proof.
Ask by Cox Norris. in the United States
Jan 10,2025
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To prove
, we will utilize the given information and the Side-Angle-Side (SAS) congruence criterion.
-
Identify the Components:
- Since
is the midpoint of , we have . Let’s denote this length as . - The given
means that we have a common side and, as a result, is an equal distance from points and . - We also have
as given.
- Since
-
Use Congruent Segments and Angles:
- So far, we have
(both equal to ), and (let’s denote this length as ). - The angles
and are congruent by the problem statement.
- So far, we have
-
Application of the SAS Congruence Criterion:
- According to SAS, for
and to be congruent, we need two sides and the included angle of one triangle to be equal to those of the other triangle:- Side
(both equal to ), - Angle
, - Side
(an arbitrary segment) should equal (since they serve as the corresponding sides opposite the equal angles from point ).
- Side
- According to SAS, for
-
Conclusion:
- With these components established, we have
, , and . Hence we conclude that:
This is based on the SAS criterion confirming the triangles are congruent through our established equalities! - With these components established, we have