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Given: is the midpoint of and .
Prove: .
Note: quadrilateral properties are not permitted in this proof.

Ask by Cox Norris. in the United States
Jan 10,2025

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is congruent to by the Side-Angle-Side (SAS) Congruence Postulate.

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To prove , we will utilize the given information and the Side-Angle-Side (SAS) congruence criterion.
  1. Identify the Components:
    • Since is the midpoint of , we have . Let’s denote this length as .
    • The given means that we have a common side and, as a result, is an equal distance from points and .
    • We also have as given.
  2. Use Congruent Segments and Angles:
    • So far, we have (both equal to ), and (let’s denote this length as ).
    • The angles and are congruent by the problem statement.
  3. Application of the SAS Congruence Criterion:
    • According to SAS, for and to be congruent, we need two sides and the included angle of one triangle to be equal to those of the other triangle:
      • Side (both equal to ),
      • Angle ,
      • Side (an arbitrary segment) should equal (since they serve as the corresponding sides opposite the equal angles from point ).
  4. Conclusion:
    • With these components established, we have , , and . Hence we conclude that:
    This is based on the SAS criterion confirming the triangles are congruent through our established equalities!

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