Question
Identify which of the commutative, associative, and/or distributive laws are being
illustrated in the following examples:
\( \begin{array}{ll}\text { Q.2.3.1 }

Identify which of the commutative, associative, and/or distributive laws are being illustrated in the following examples: \( \begin{array}{ll}\text { Q.2.3.1 } & \text { Distributive law }(15 \times 7) \times 9=15 \times 7 \times 9 \\ \text { Q.2.3.2 } & 29 \times(5+17)=29 \times 5+29 \times 17\end{array} \)

Ask by Fernandez Patel.
Mar 15,2025 14:53

UpStudy AI Solution

Tutor-Verified Answer

Answer

Q.2.3.1 illustrates the associative law, and Q.2.3.2 illustrates the distributive law.

Solution

We start with the two expressions and determine which algebraic law each one illustrates. ### Q.2.3.1 The expression is \[ (15 \times 7) \times 9 = 15 \times 7 \times 9. \] Here, the grouping of the factors is changed without altering the order. In general, the associative law for multiplication states that \[ (a \times b) \times c = a \times (b \times c). \] In this expression, the parentheses are removed, which is a direct application of the associative law. Therefore, **Q.2.3.1 illustrates the associative law**. ### Q.2.3.2 The expression is \[ 29 \times (5+17)=29 \times 5+29 \times 17. \] In this case, the multiplication is distributed over the addition inside the parentheses. The distributive law states that \[ a \times (b+c)=a \times b+a \times c. \] Thus, **Q.2.3.2 illustrates the distributive law**. In summary: - Q.2.3.1 uses the **associative law**. - Q.2.3.2 uses the **distributive law**.

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The Deep Dive

In Q.2.3.1, you can observe the distributive law at work! The equation showcases how multiplication distributes over addition, but it's more about viewing the multiplication involved rather than a direct application. Think of it as spreading out the numbers while keeping their relationships intact! Moving on to Q.2.3.2, this example beautifully illustrates the distributive law in action. It reinforces the idea that multiplying a number by a sum is the same as multiplying it by each addend and then adding the results. It’s like sharing your favorite ice cream among friends – everyone gets a scoop, and you still have the same total amount!
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