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\( \leftarrow \begin{array}{l}\text { Graph the linear equation. } \\ 4 x+2 y=16\end{array} \)

Ask by Chan Peterson. in the United States
Feb 02,2025

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To graph the equation \(4x + 2y = 16\), first rewrite it in slope-intercept form \(y = -2x + 8\). Plot the y-intercept at \((0, 8)\) and another point like \((2, 4)\). Draw a straight line through these points to represent the equation.

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Mind Expander

To graph the equation \(4x + 2y = 16\), you can start by rewriting it in slope-intercept form, \(y = mx + b\). Rearranging gives \(2y = -4x + 16\) and then \(y = -2x + 8\). The slope is -2, meaning the line goes down 2 units for every 1 unit it goes to the right. The y-intercept is 8, so you can plot the point (0, 8) on the y-axis. From there, use the slope to find another point, like (1, 6). Connecting these points will give you your line! Another fun way to graph is by finding the intercepts! For the x-intercept, set \(y = 0\) and solve \(4x = 16\), giving you \(x = 4\) (point (4, 0)). For the y-intercept, set \(x = 0\) to solve \(2y = 16\), giving \(y = 8\) (point (0, 8)). Plot these two points on a graph, draw a straight line through them, and voilà! You've graphed your linear equation beautifully.

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