\( 1 \leqslant \) Question \( 23,6.3 . \mathrm{B}-28 \), HW Score: \( 95.65 \%, 22 \) of 23 If \( \frac{1}{34} \) of all rabbits in a country are in one state and \( \frac{2}{7} \) of the rabbits are in a different state, what total fractional part of the rabbit population is not in those two states? The total fractional part of the rabbit population not living in the two states is 0 of 1 (Type an integer or a simplified fraction.)

To find the total fractional part of the rabbit population not in the two states, we start by summing the fractions of rabbits in each state: \[ \frac{1}{34} + \frac{2}{7} \] To add these, we need a common denominator. The least common multiple of 34 and 7 is 238. Converting each fraction: \[ \frac{1}{34} = \frac{7}{238}, \quad \text{and} \quad \frac{2}{7} = \frac{68}{238} \] Now, add the fractions: \[ \frac{7}{238} + \frac{68}{238} = \frac{75}{238} \] The total fraction of rabbits in these two states is \(\frac{75}{238}\). To find the part of the rabbit population not in those two states, we subtract this from the whole: \[ 1 - \frac{75}{238} = \frac{238 - 75}{238} = \frac{163}{238} \] Thus, the total fractional part of the rabbit population not living in the two states is: \[ \frac{163}{238} \] So the answer to your question is \( \frac{163}{238} \).