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\( 1 \leqslant \) Question \( 23,6.3 . \mathrm{B}-28 \), HW Score: \( 95.65 \%, 22 \) of 23 If \( \frac{1}{34} \) of all rabbits in a country are in one state and \( \frac{2}{7} \) of the rabbits are in a different state, what total fractional part of the rabbit population is not in those two states? The total fractional part of the rabbit population not living in the two states is 0 of 1 (Type an integer or a simplified fraction.)

Ask by Norris Rodriquez. in the United States
Jan 25,2025

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Tutor-Verified Answer

Answer

The fractional part of the rabbit population not in the two states is \(\frac{163}{238}\).

Solution

To determine the fractional part of the rabbit population **not** living in the two specified states, follow these steps: 1. **Identify the Fractions in the Two States:** - **State 1:** \(\frac{1}{34}\) of all rabbits. - **State 2:** \(\frac{2}{7}\) of all rabbits. 2. **Calculate the Combined Fraction in Both States:** \[ \frac{1}{34} + \frac{2}{7} \] To add these fractions, find a common denominator. The least common multiple (LCM) of 34 and 7 is 238. \[ \frac{1}{34} = \frac{7}{238} \quad \text{and} \quad \frac{2}{7} = \frac{68}{238} \] \[ \frac{7}{238} + \frac{68}{238} = \frac{75}{238} \] 3. **Determine the Fraction Not in Either State:** Subtract the combined fraction from the whole population (which is \(1\) or \(\frac{238}{238}\)). \[ 1 - \frac{75}{238} = \frac{238}{238} - \frac{75}{238} = \frac{163}{238} \] 4. **Simplify the Fraction (if possible):** - **163** is a prime number. - **238** factors into \(2 \times 7 \times 17\). Since there are no common factors between **163** and **238**, the fraction is already in its simplest form. **Final Answer:** \[ \frac{163}{238} \]

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To find the total fractional part of the rabbit population not in the two states, we start by summing the fractions of rabbits in each state: \[ \frac{1}{34} + \frac{2}{7} \] To add these, we need a common denominator. The least common multiple of 34 and 7 is 238. Converting each fraction: \[ \frac{1}{34} = \frac{7}{238}, \quad \text{and} \quad \frac{2}{7} = \frac{68}{238} \] Now, add the fractions: \[ \frac{7}{238} + \frac{68}{238} = \frac{75}{238} \] The total fraction of rabbits in these two states is \(\frac{75}{238}\). To find the part of the rabbit population not in those two states, we subtract this from the whole: \[ 1 - \frac{75}{238} = \frac{238 - 75}{238} = \frac{163}{238} \] Thus, the total fractional part of the rabbit population not living in the two states is: \[ \frac{163}{238} \] So the answer to your question is \( \frac{163}{238} \).

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