TRANSFORM THE GIVEN EQUATION IN:- $$ 3 x+2 y-18=0 $$ a) SLOPE-INTERCEPT FORM $$ (y=m x+c) $$ b) TWO INTERCEPTS FORM $$ \left[\frac{x}{a}+\frac{y}{b}=1\right] $$

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**Step 1. Write the given equation:**

$$
3x + 2y - 18 = 0
$$

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**(a) Slope-Intercept Form $$\left(y = mx + c\right)$$:**

1. Isolate the $$y$$-term:

$$
   2y = -3x + 18
   $$

2. Divide by $$2$$:

$$
   y = -\frac{3}{2}x + 9
   $$

Thus, the slope-intercept form is:

$$
y = -\frac{3}{2}x + 9
$$

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**(b) Two Intercepts Form $$\left[\frac{x}{a} + \frac{y}{b} = 1\right]$$:**

1. Find the $$x$$-intercept by letting $$y = 0$$:

$$
   3x - 18 = 0 \quad \Rightarrow \quad 3x = 18 \quad \Rightarrow \quad x = 6
   $$

So, $$a = 6$$.

2. Find the $$y$$-intercept by letting $$x = 0$$:

$$
   2y - 18 = 0 \quad \Rightarrow \quad 2y = 18 \quad \Rightarrow \quad y = 9
   $$

So, $$b = 9$$.

3. Substitute into the intercept form:

$$
   \frac{x}{6} + \frac{y}{9} = 1
   $$

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**Final Answers:**

- Slope-Intercept Form: $$\displaystyle y = -\frac{3}{2}x + 9$$
- Two Intercepts Form: $$\displaystyle \frac{x}{6} + \frac{y}{9} = 1$$
**Transformed Equation:** - **Slope-Intercept Form:** $$ y = -\frac{3}{2}x + 9 $$ - **Two Intercepts Form:** $$ \frac{x}{6} + \frac{y}{9} = 1 $$

TRANSFORM THE GIVEN
EQUATION IN:-

a) SLOPE-INTERCEPT FORM
b) TWO INTERCEPTS FORM

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TRANSFORM THE GIVEN EQUATION IN:- a) SLOPE-INTERCEPT FORM b) TWO INTERCEPTS FORM