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Victoria Morefield 02/03/25 5:02 AM ce-compound Cuastion 18, \( 4,8.84 \) HWS Scces \( 40 \% 8 \) of 20 polnts Politss0 of 1 Save Suppose you start saving today for a \( \$ 30,000 \) down payment that you plan to mako on a house in 7 years. Assurre hal you make no deposits into the account after the initial deposit. For the accounl described below, how much would you have to deposit now to reach your \( \$ 30,000 \) goal in 7 years. An account wilt daily compounding and an APR of \( 8 \% \) You should invest \( \$ \) \( \square \) (Do not round until the final answer. Nenen raurd to two docimal paces as reeted.)

Ask by Hampton Vargas. in the United States
Feb 03,2025

Real Tutor Solution

Tutor-Verified Answer

Answer

You need to deposit approximately $5,741,791 now to reach your $30,000 goal in 7 years with daily compounding at an APR of 8%.

Solution

To determine how much you need to deposit now to reach your $30,000 goal in 7 years with daily compounding and an APR of 8%, we can use the formula for compound interest: \[ A = P \left(1 + \frac{r}{n}\right)^{nt} \] Where: - \( A \) is the future value of the investment (in this case, $30,000) - \( P \) is the principal amount (the initial deposit) - \( r \) is the annual interest rate (8% in this case) - \( n \) is the number of times the interest is compounded per year (365 for daily compounding) - \( t \) is the time in years (7 years in this case) We need to solve for \( P \) to find out how much you need to deposit now to reach your goal in 7 years. Calculate the value by following steps: - step0: Calculate: \(30000\left(1+\frac{8}{365}\right)^{365}\times 7\) - step1: Add the numbers: \(30000\left(\frac{373}{365}\right)^{365}\times 7\) - step2: Multiply the terms: \(210000\left(\frac{373}{365}\right)^{365}\) - step3: Simplify: \(210000\times \frac{373^{365}}{365^{365}}\) - step4: Rewrite the expression: \(625\times 336\times \frac{373^{365}}{365^{365}}\) - step5: Rewrite the expression: \(625\times 336\times \frac{373^{365}}{5^{365}\times 73^{365}}\) - step6: Rewrite the expression: \(5^{4}\times 336\times \frac{373^{365}}{5^{365}\times 73^{365}}\) - step7: Reduce the numbers: \(336\times \frac{373^{365}}{5^{361}\times 73^{365}}\) - step8: Multiply the fractions: \(\frac{336\times 373^{365}}{5^{361}\times 73^{365}}\) The amount you need to deposit now to reach your $30,000 goal in 7 years with daily compounding and an APR of 8% is approximately $5,741,791. Therefore, you would need to deposit $5,741,791 now to reach your $30,000 goal in 7 years.

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Bonus Knowledge

To reach your goal of a \$30,000 down payment in 7 years with an 8% APR compounded daily, you can use the formula for present value \( PV = \frac{FV}{(1 + r/n)^{nt}} \). Here, \( FV \) is your future value of \$30,000, \( r \) is the annual interest rate (0.08), \( n \) is the number of compounding periods per year (365), and \( t \) is the time in years (7). Plugging in these values will give you the amount you need to deposit now. So, calculating this, you find that you will need to deposit approximately \$14,574.07 today to reach your goal of \$30,000 in 7 years! That’s a solid strategy for future homeownership!

Related Questions

EXERCISES 4.1 Write cach expression in Exercises \( 1-14 \) in the form \( 2^{\text {ks }} \) or \( 3^{k t} \), for a suitable constant \( k \). (1) \( 4^{x},(\sqrt{3})^{x},\left(\frac{1}{3}\right)^{x} \) 2. \( 27^{x} \cdot(\sqrt[3]{2})^{x},\left(\frac{1}{8}\right)^{2} \) (3) \( 8^{2 x / 3}, 9^{3 x / 2}, 16^{-3 x / 4} \) 4. \( 9^{-x / 2}, 8^{4 x / 3}, 27^{-2 x / 3} \) (5.) \( \left(\frac{1}{4}\right)^{2 x},\left(\frac{1}{8}\right)^{-3 x},\left(\frac{1}{81}\right)^{x / 2} \) 6. \( \left(\frac{1}{9}\right)^{2 x},\left(\frac{1}{27}\right)^{x / 3},\left(\frac{1}{16}\right)^{-x / 2} \) 7. \( 6^{x} \cdot 3^{-x}, \frac{15^{x}}{5^{x}}, \frac{12^{x}}{2^{2 x}} \) 8. \( 7^{-x} \cdot 14^{x}, \frac{2^{x}}{6^{x}}, \frac{3^{2 x}}{18^{x}} \) 9. \( \frac{3^{4 x}}{3^{2 x}}, \frac{2^{5 x+1}}{2 \cdot 2^{-x}}, \frac{9^{-x}}{27^{-x / 3}} \) 10. \( \frac{2^{x}}{6^{x}}, \frac{3^{-5 x}}{3^{-2 x}}, \frac{16^{x}}{8^{-x}} \) 11. \( 2^{3 x} \cdot 2^{-5 x / 2}, 3^{2 x} \cdot\left(\frac{1}{3}\right)^{2 x / 3} \) 12. \( 2^{5 x / 4} \cdot\left(\frac{1}{2}\right)^{x}, 3^{-2 x} \cdot 3^{5 x / 2} \) (13.) \( \left(2^{-3 x} \cdot 2^{-2 x}\right)^{2 / 5},\left(9^{1 / 2} \cdot 9^{4}\right)^{x / 9} \) 14. \( \left(3^{-x} \cdot 3^{x / 5}\right)^{5},\left(16^{1 / 4} \cdot 16^{-3 / 4}\right)^{3 x} \) 15. Find a number \( b \) such that the function \( f(x)=3^{-2 x} \) can be written in the form \( f(x)=b^{x} \). 16. Find \( b \) so that \( 8^{-x / 3}=b^{x} \) for all \( x \). Solve the following equations for \( x \). (17) \( 5^{2 x}=5^{2} \) 18. \( 10^{-x}=10^{2} \) 19. \( (2.5)^{2 x+1}=(2.5)^{5} \) 20. \( (3.2)^{x-3}=(3.2)^{5} \) 21. \( 10^{1-x}=100 \) 22. \( 2^{4-x}=8 \) 23. \( 3(2.7)^{5 x}=8.1 \) 24. \( 4(2.7)^{2 x-1}=10.8 \) 25. \( \left(2^{x+1} \cdot 2^{-3}\right)^{2}=2 \) 26. \( \left(3^{2 x} \cdot 3^{2}\right)^{4}=3 \)
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