\( \left(\frac{7}{2}, 0\right) \) is a solution of \( 2 x+k y-7=0 \) then \( \mathrm{k}= \)

To find the value of \( k \), we will substitute the solution \( \left(\frac{7}{2}, 0\right) \) into the equation \( 2x + ky - 7 = 0 \). Substituting \( x = \frac{7}{2} \) and \( y = 0 \): \[ 2 \left(\frac{7}{2}\right) + k(0) - 7 = 0 \] This simplifies to: \[ 7 - 7 = 0 \] Since this holds true for any \( k \), we deduce that \( k \) can be any real number. Thus, there is no unique value for \( k \) based on this equation alone.