\( \left(\frac{7}{2}, 0\right) \) is a solution of \( 2 x+k y-7=0 \) then \( \mathrm{k}= \)

To find the value of \( k \) given that \( \left(\frac{7}{2}, 0\right) \) is a solution of the equation \( 2x + ky - 7 = 0 \), we can substitute \( x = \frac{7}{2} \) and \( y = 0 \) into the equation. 1. Substitute \( x \) and \( y \) into the equation: \[ 2\left(\frac{7}{2}\right) + k(0) - 7 = 0 \] 2. Simplify the equation: \[ 7 + 0 - 7 = 0 \] This simplifies to: \[ 0 = 0 \] Since the equation holds true for any value of \( k \) when \( y = 0 \), we can conclude that \( k \) can be any real number. Thus, the value of \( k \) is not uniquely determined by the given information.