Question
- The function
and
are defined as
a. State the range of
b. Find the domain of
c. Sketch the graph of
indicating the intercepts with the
-axis
d. State with a reason, whether
is injective or not
a. State the range of
b. Find the domain of
c. Sketch the graph of
d. State with a reason, whether
Ask by Warren Schofield. in Zimbabwe
Jan 16,2025
Upstudy AI Solution
Tutor-Verified Answer
Answer
The function
is not injective because different inputs can produce the same output.
Solution
d. Determining Whether
is Injective
A function is injective (or one-to-one) if every element of the function’s range is mapped by exactly one element of its domain. In other words, for
to be injective, whenever
, it must follow that
.
Let’s analyze the function
:
-
Symmetry Analysis:
- The function
is a symmetric function about the y-axis because for all .
- The function
-
Testing Injectivity:
- Consider two different inputs:
and where . - Compute
and . - Here,
even though .
- Consider two different inputs:
-
Conclusion:
- Since there exist distinct values
and such that , the function is not injective.
- Since there exist distinct values
Reason: The function
is symmetric about the y-axis, meaning that
for any
. Therefore, distinct inputs
and
produce the same output, violating the condition for injectivity.
Answer Summary:
Problem 4.d Answer:
The function
is not injective because
for any real number
, meaning distinct inputs can produce the same output.
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Extra Insights
The function
is a downward-opening parabola with its vertex at
. The range of
is
since as
moves away from 0,
decreases without bound.
For the function
to be defined,
must be non-negative. Thus, we need to find when
, which simplifies to
, or
. Therefore, the domain of
is the interval
.
To sketch
, we first identify that
touches the x-axis when
, which occurs at
. Thus, the intercepts are at points
and
. The function
will reflect the negative part of
across the x-axis, so between the intercepts, the graph will rise to a maximum of 4 at
and then drop back to 0 on either side.
The function
is not injective (or one-to-one) because it fails the horizontal line test. For example, both
and
yield a value of 3 (i.e.,
). This means there are multiple
values that produce the same output, confirming that
is not injective.