Question
\( x^{2}+12 x+45=0 \). Enter multiple answers as a list separated by commas. Example: \( 2+2 i, 2-2 i \)
Ask by Simpson Chandler. in the United States
Jan 23,2025
Real Tutor Solution
Tutor-Verified Answer
Answer
The solutions are \(x=-6-3i\) and \(x=-6+3i\).
Solution
Solve the equation \( x^{2}+12x+45=0 \).
Solve the equation(The complex numbers system) by following steps:
- step0: Solve using the quadratic formula in the complex numbers system:
\(x^{2}+12x+45=0\)
- step1: Solve using the quadratic formula:
\(x=\frac{-12\pm \sqrt{12^{2}-4\times 45}}{2}\)
- step2: Simplify the expression:
\(x=\frac{-12\pm \sqrt{-36}}{2}\)
- step3: Simplify the expression:
\(x=\frac{-12\pm 6i}{2}\)
- step4: Separate into possible cases:
\(\begin{align}&x=\frac{-12+6i}{2}\\&x=\frac{-12-6i}{2}\end{align}\)
- step5: Simplify the expression:
\(\begin{align}&x=-6+3i\\&x=\frac{-12-6i}{2}\end{align}\)
- step6: Simplify the expression:
\(\begin{align}&x=-6+3i\\&x=-6-3i\end{align}\)
- step7: Rewrite:
\(x_{1}=-6-3i,x_{2}=-6+3i\)
- step8: Remove the complex number(s):
\(\textrm{No real solution}\)
The equation \(x^{2}+12x+45=0\) does not have any real solutions. Therefore, the solutions are complex numbers.
Solve the equation(The complex numbers system) by following steps:
- step0: Solve using the quadratic formula in the complex numbers system:
\(x^{2}+12x+45=0\)
- step1: Solve using the quadratic formula:
\(x=\frac{-12\pm \sqrt{12^{2}-4\times 45}}{2}\)
- step2: Simplify the expression:
\(x=\frac{-12\pm \sqrt{-36}}{2}\)
- step3: Simplify the expression:
\(x=\frac{-12\pm 6i}{2}\)
- step4: Separate into possible cases:
\(\begin{align}&x=\frac{-12+6i}{2}\\&x=\frac{-12-6i}{2}\end{align}\)
- step5: Simplify the expression:
\(\begin{align}&x=-6+3i\\&x=\frac{-12-6i}{2}\end{align}\)
- step6: Simplify the expression:
\(\begin{align}&x=-6+3i\\&x=-6-3i\end{align}\)
- step7: Rewrite:
\(x_{1}=-6-3i,x_{2}=-6+3i\)
The solutions to the equation \(x^{2}+12x+45=0\) are \(x=-6-3i\) and \(x=-6+3i\).
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Bonus Knowledge
To solve the quadratic equation \( x^{2}+12 x+45=0 \), we can use the quadratic formula: \[ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \] Here, \( a = 1 \), \( b = 12 \), and \( c = 45 \). First, we calculate the discriminant: \[ b^2 - 4ac = 12^2 - 4(1)(45) = 144 - 180 = -36 \] Since the discriminant is negative, the solutions will be complex numbers. Now substituting into the quadratic formula: \[ x = \frac{-12 \pm \sqrt{-36}}{2(1)} = \frac{-12 \pm 6i}{2} = -6 \pm 3i \] The solutions are: \[ -6 + 3i, -6 - 3i \]