Simplify \( \frac{x^{3}-6 x^{2}+9 x}{x^{3}-3 x^{2}} \)
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To simplify the expression \( \frac{x^{3}-6 x^{2}+9 x}{x^{3}-3 x^{2}} \), we first factor both the numerator and the denominator. In the numerator: \( x^{3} - 6x^{2} + 9x = x(x^{2} - 6x + 9) = x(x - 3)^{2} \) In the denominator: \( x^{3} - 3x^{2} = x^{2}(x - 3) \) Now, substituting these factored forms into the original expression, we have: \[ \frac{x(x - 3)^{2}}{x^{2}(x - 3)} \] We can cancel one \( x \) from the numerator and one \( (x - 3) \) from the denominator (as long as \( x \neq 0 \) and \( x \neq 3 \)): \[ \frac{(x - 3)}{x} \] Thus, the simplified expression is: \[ \frac{x - 3}{x}, \quad x \neq 0, x \neq 3 \]