c. \( -2 x-5<2 \) d. \( -6(x-3) \geq 2-2(x-8) \)

To solve the inequality \( -2x - 5 < 2 \), start by adding 5 to both sides, giving you \( -2x < 7 \). Then, divide by -2, remembering to flip the inequality sign, resulting in \( x > -\frac{7}{2} \) or \( x > -3.5 \). For the second inequality \( -6(x-3) \geq 2 - 2(x-8) \), distribute both sides: \( -6x + 18 \geq 2 - 2x + 16 \) which simplifies to \( -6x + 18 \geq 18 - 2x \). Adding \( 6x \) and subtracting 18 from both sides yields \( 0 \geq 4x \), thus \( x \leq 0 \).