Divide the following rational expressions. Write the answer in lowest terms. \( \frac{5 x-15}{35}+\frac{7 x-21}{5} \)
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To divide the rational expressions, we first set up the expression: \[ \frac{5x-15}{35} + \frac{7x-21}{5} \] Now, we will factor each numerator: 1. \(5x - 15 = 5(x - 3)\) 2. \(7x - 21 = 7(x - 3)\) Now, rewrite the expression: \[ \frac{5(x - 3)}{35} + \frac{7(x - 3)}{5} \] Next, we simplify \( \frac{5(x - 3)}{35} \): \[ \frac{5(x - 3)}{35} = \frac{x - 3}{7} \] Now rewriting our expression, we have: \[ \frac{x - 3}{7} + \frac{7(x - 3)}{5} \] Now let's find a common denominator, which would be \(35\): For the first term: \[ \frac{x - 3}{7} = \frac{5(x - 3)}{35} \] So now we rewrite our expression with a common denominator: \[ \frac{5(x - 3)}{35} + \frac{49(x - 3)}{35} = \frac{5(x - 3) + 49(x - 3)}{35} \] Combining the numerators: \[ = \frac{(5 + 49)(x - 3)}{35} = \frac{54(x - 3)}{35} \] Thus, our answer in lowest terms is: \[ \frac{54(x - 3)}{35} \]