Factor each completely. $$ \begin{array}{ll} ext { 1) } b^{2}+8 b+7 & ext { 2) } n^{2}-11 n+10 \ ext { 3) } m^{2}+m-90 & ext { 4) } n^{2}+4 n-12\end{array} $$

Question

Factor each completely. $$ \begin{array}{ll}	ext { 1) } b^{2}+8 b+7 & 	ext { 2) } n^{2}-11 n+10 \ 	ext { 3) } m^{2}+m-90 & 	ext { 4) } n^{2}+4 n-12\end{array} $$

UpStudy AI · Accepted Answer

Sure, let's factor each quadratic expression completely:

1) **$$ b^{2} + 8b + 7 $$**
   
   We need two numbers that multiply to **+7** and add to **+8**.
   
   The numbers are **7** and **1**.
   
   **Factored form:** $$ (b + 7)(b + 1) $$

2) **$$ n^{2} - 11n + 10 $$**
   
   We need two numbers that multiply to **+10** and add to **-11**.
   
   The numbers are **-10** and **-1**.
   
   **Factored form:** $$ (n - 10)(n - 1) $$

3) **$$ m^{2} + m - 90 $$**
   
   We need two numbers that multiply to **-90** and add to **+1**.
   
   The numbers are **10** and **-9**.
   
   **Factored form:** $$ (m + 10)(m - 9) $$

4) **$$ n^{2} + 4n - 12 $$**
   
   We need two numbers that multiply to **-12** and add to **+4**.
   
   The numbers are **6** and **-2**.
   
   **Factored form:** $$ (n + 6)(n - 2) $$

**Summary of Factored Forms:**
1. $$ (b + 7)(b + 1) $$
2. $$ (n - 10)(n - 1) $$
3. $$ (m + 10)(m - 9) $$
4. $$ (n + 6)(n - 2) $$
1. $$ (b + 7)(b + 1) $$ 2. $$ (n - 10)(n - 1) $$ 3. $$ (m + 10)(m - 9) $$ 4. $$ (n + 6)(n - 2) $$

Factor each completely.

Upstudy AI Solution

Answer

Solution

Mind Expander

Related Questions

Latest Algebra Questions