What is wrong with the following attempted c-string declaration and initialization? char str1[5] = \{'a', 'b', 'c'\}; The single quotes should be double quotes. The values do not constitute a c-string. There are only 3 values in the braces. nothing

The values do not constitute a C-string. In C, a C-string is an array of characters that ends with a null terminator (`'\0'`). In your example, `char str1[5] = {'a', 'b', 'c'};`, the array is missing the null terminator, so it would not be recognized as a proper C-string. You might want to initialize it like this: `char str1[5] = {'a', 'b', 'c', '\0'};`. Additionally, while the array can hold 5 characters, it only initializes the first three. It's important to ensure that when you declare an array, you have enough space for all intended characters plus one for the null terminator. Otherwise, you might run into unexpected behavior when using string functions that rely on that null terminator!