Question
Example 7
What is the smallest number of terms of the
geometrical progression,
,
that will give a total greater than 6000000 ?
What is the smallest number of terms of the
geometrical progression,
that will give a total greater than 6000000 ?
Ask by Nguyen Wagner. in Ghana
Dec 26,2024
Upstudy AI Solution
Tutor-Verified Answer
Answer
13 terms are needed to exceed a total of 6,000,000.
Solution

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The Deep Dive
To find the smallest number of terms in the geometric progression
such that their sum exceeds 6,000,000, let’s first identify the first term and the common ratio. The first term,
, and the common ratio can be determined by dividing the second term by the first:
.
The sum of the first
terms of a geometric progression is given by the formula:
Plugging our values into the formula gives us:
We need to find the smallest
such that:
This simplifies to:
Therefore:
Next, we can take logarithms to solve for
:
Now, calculate
and
.
Dividing both sides results in:
Since
must be a whole number, we round up to find
.
Thus, the smallest number of terms required for the sum to exceed 6,000,000 is 13.