Factor the trinomial completely. $$ x^{2}-23 x+60 $$

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Factor the expression $$ x^{2}-23x+60 $$.
Factor the expression by following steps:
- step0: Factor:
  $$x^{2}-23x+60$$
- step1: Rewrite the expression:
  $$x^{2}+\left(-3-20\right)x+60$$
- step2: Rewrite the expression:
  $$x^{2}-3x-20x+60$$
- step3: Factor the expression:
  $$x\left(x-3\right)-20\left(x-3\right)$$
- step4: Factor the expression:
  $$\left(x-20\right)\left(x-3\right)$$
The trinomial $$x^{2}-23x+60$$ can be factored completely as $$(x-20)(x-3)$$.
$$ x^{2}-23x+60 = (x-20)(x-3) $$

Factor the trinomial completely.

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