Question
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Sire bought 3 slices of pizza and 2 orders of fries for a total of \( \$ 21 \). The cost of one slice of pizza is \( \$ 2.00 \) more than the costs of one order of fries. What is the COMBINED costs of one slice of pizza and one order of fries?

Ask by Lawson Norris. in the United States
Jan 23,2025

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Tutor-Verified Answer

Answer

The combined cost of one slice of pizza and one order of fries is \$8.

Solution

Let's solve the problem step by step. **Let:** - \( P \) = cost of one slice of pizza - \( F \) = cost of one order of fries **Given:** 1. Sire bought 3 slices of pizza and 2 orders of fries for a total of \$21: \[ 3P + 2F = 21 \] 2. The cost of one slice of pizza is \$2.00 more than one order of fries: \[ P = F + 2 \] **Step 1: Substitute \( P \) in the first equation** Replace \( P \) with \( F + 2 \) in the equation \( 3P + 2F = 21 \): \[ 3(F + 2) + 2F = 21 \] **Step 2: Simplify the equation** \[ 3F + 6 + 2F = 21 \] \[ 5F + 6 = 21 \] **Step 3: Solve for \( F \)** \[ 5F = 21 - 6 \] \[ 5F = 15 \] \[ F = 3 \] **Step 4: Solve for \( P \)** Using \( P = F + 2 \): \[ P = 3 + 2 = 5 \] **Combined Cost of One Slice of Pizza and One Order of Fries:** \[ P + F = 5 + 3 = \$8 \] **Answer:** The combined cost of one slice of pizza and one order of fries is **\$8**.

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Let the cost of one order of fries be \( x \). Therefore, the cost of one slice of pizza would be \( x + 2 \). According to the problem, Sire bought 3 slices of pizza and 2 orders of fries, which gives us the equation: \[ 3(x + 2) + 2x = 21 \] Expanding this, we get: \[ 3x + 6 + 2x = 21 \] Combining like terms: \[ 5x + 6 = 21 \] Subtracting 6 from both sides: \[ 5x = 15 \] Dividing by 5: \[ x = 3 \] Thus, the cost of one order of fries is \( \$3 \), and the cost of one slice of pizza is: \[ 3 + 2 = 5 \] Now, to find the combined cost of one slice of pizza and one order of fries: \[ 3 + 5 = 8 \] So, the combined costs of one slice of pizza and one order of fries is \( \$8 \).

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