$$ \begin{array}{l} =(6+2)+4= \ (16+2)+4=6+(2+4) \quad 12=12 \ 8 \times(10 \times 4)= \end{array} $$ Solve it: b. $$ (7+3)+1= $$ d. $$ 4 \times(5 \times 2)= $$ $$ 11 \times 31 \times 2= $$

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UpStudy AI · Accepted Answer

Sure, let's solve each part step by step:

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**b. $$ (7 + 3) + 1 $$**

1. **Add the numbers inside the first parentheses:**
   $$
   7 + 3 = 10
   $$
2. **Add the result to 1:**
   $$
   10 + 1 = 11
   $$

**Answer:** $$ 11 $$

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**d. $$ 4 \times (5 \times 2) $$**

1. **Multiply the numbers inside the parentheses first:**
   $$
   5 \times 2 = 10
   $$
2. **Multiply the result by 4:**
   $$
   4 \times 10 = 40
   $$

**Answer:** $$ 40 $$

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**$$ 11 \times 31 \times 2 $$**

1. **First, multiply 11 by 31:**
   $$
   11 \times 31 = 341
   $$
2. **Then, multiply the result by 2:**
   $$
   341 \times 2 = 682
   $$

**Answer:** $$ 682 $$

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**b. $$ (7 + 3) + 1 = 11 $$ d. $$ 4 \times (5 \times 2) = 40 $$ $$ 11 \times 31 \times 2 = 682 $$**

Solve it:
b.
d.

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Solve it: b. d.