\[ \begin{array}{l} =(6+2)+4= \\ (16+2)+4=6+(2+4) \quad 12=12 \\ 8 \times(10 \times 4)= \end{array} \] Solve it: b. \( (7+3)+1= \) d. \( 4 \times(5 \times 2)= \) \[ 11 \times 31 \times 2= \]

To solve \( (7+3)+1 \), first add \( 7 \) and \( 3 \) to get \( 10 \). Then, add \( 1 \): \( 10 + 1 = 11 \). Therefore, \( (7+3)+1 = 11 \). For \( 4 \times (5 \times 2) \), start by calculating \( 5 \times 2 \) which equals \( 10 \). Next, multiply that result by \( 4 \): \( 4 \times 10 = 40 \). Thus, \( 4 \times (5 \times 2) = 40 \). Now for \( 11 \times 31 \times 2 \), calculate \( 11 \times 31 \) first, which equals \( 341 \). Then, multiply this result by \( 2 \): \( 341 \times 2 = 682 \). Therefore, \( 11 \times 31 \times 2 = 682 \).