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Rewrite the equation \( 3 x-4 y=12 \) in slope-intercept form, solving for \( y \). Show your work.

Ask by Floyd Tyler. in the United States
Jan 23,2025

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Answer

To rewrite \( 3x - 4y = 12 \) in slope-intercept form, solve for \( y \): 1. Subtract \( 3x \) from both sides: \[ -4y = -3x + 12 \] 2. Divide every term by \( -4 \): \[ y = \frac{3}{4}x - 3 \] So, the slope-intercept form is: \[ y = \frac{3}{4}x - 3 \]

Solution

To rewrite the equation \( 3x - 4y = 12 \) into **slope-intercept form** (\( y = mx + b \)), where \( m \) is the slope and \( b \) is the y-intercept, follow these steps: 1. **Start with the original equation:** \[ 3x - 4y = 12 \] 2. **Isolate the term containing \( y \) by moving \( 3x \) to the other side:** \[ -4y = -3x + 12 \] 3. **Solve for \( y \) by dividing every term by \( -4 \):** \[ y = \frac{-3x + 12}{-4} \] 4. **Simplify the equation:** \[ y = \frac{3}{4}x - 3 \] So, the **slope-intercept form** of the equation is: \[ y = \frac{3}{4}x - 3 \] **Interpretation:** - **Slope (\( m \))**: \( \frac{3}{4} \) - **Y-intercept (\( b \))**: \( -3 \) This means the line has a slope of \( \frac{3}{4} \) and crosses the y-axis at the point \( (0, -3) \).

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To rewrite the equation \( 3x - 4y = 12 \) in slope-intercept form, we need to solve for \( y \). 1. Start with the original equation: \( 3x - 4y = 12 \) 2. Subtract \( 3x \) from both sides: \( -4y = -3x + 12 \) 3. Now, divide every term by \(-4\) to isolate \(y\): \( y = \frac{3}{4}x - 3 \) Now, the equation is in slope-intercept form \( y = mx + b \), where the slope \( m = \frac{3}{4} \) and the y-intercept \( b = -3 \).

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