\( 1 \in \quad \) In the following exorcise, find the coordinates of the vertex for the parabola defined by the given quadratic function \[ \left(f(x)=2(x-8)^{2}+1\right. \] The vertex is \( \square \) (Type an ordered pais )

The given quadratic function is in vertex form, which is expressed as \( f(x) = a(x-h)^2 + k \), where \( (h, k) \) represents the vertex. From your function \( f(x) = 2(x-8)^2 + 1 \), we can easily see that \( h = 8 \) and \( k = 1 \). Thus, the coordinates of the vertex are \( (8, 1) \). So, the vertex is \( (8, 1) \).