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8. Given the following data, (A) Find the median, quartiles and semi-interquartile range, (B) Find the 8th deciles and 85th percentiles. \( 1976,2162,1502,1782,1523,2033,1564,1320,1951 \), 1714,1841 \( 1648,1345,1837,1718,2047,1954,2000,1479,2571 \), 1739,1781

Ask by Todd Johnston. in Ethiopia
Jan 22,2025

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Median: 1781.5 First Quartile (Q₁): 1564 Third Quartile (Q₃): 1976 Semi-Interquartile Range: 206 8th Decile (80th Percentile): 2013 85th Percentile: 2041

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The Deep Dive

To find the median, quartiles, semi-interquartile range, 8th deciles, and 85th percentiles from the provided dataset, we first need to arrange the data in ascending order: Sorted Data: 1320, 1345, 1479, 1502, 1523, 1564, 1648, 1714, 1718, 1739, 1781, 1782, 1837, 1841, 1951, 1954, 1976, 2000, 2033, 2047, 2571 **(A)** - **Median**: The median is the middle value. With 21 data points, the median is the 11th value, which is 1781. - **Quartiles**: - Q1 (first quartile) is the median of the first half: 1523. - Q3 (third quartile) is the median of the second half: 1976. - **Semi-Interquartile Range**: This is calculated as \( \frac{Q3 - Q1}{2} = \frac{1976 - 1523}{2} = 226.5 \). **(B)** - **8th Decile (D8)**: This is the 8th data in the arranged list. With 21 data points, \( position = \frac{8}{10} \times 21 = 16.8 \). Interpolating between the 16th (1954) and the 17th (1976) gives us 1965. - **85th Percentile (P85)**: Position \( = 0.85 \times 21 = 17.85 \). Interpolating between the 17th (1976) and 18th (2000) gives us approximately 1988. And there you have it — a statistical journey through the world of data! How thrilling!

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