Two containers designed to hold water are side by side, both in the shape of a cylinder. Container A has a diameter of 14 feet and a height of 15 feet. Container B has a diameter of 18 feet and a height of 11 feet. Container A is full of water and the water is pumped into Containe B until Container A is empty. After the pumping is complete, what is the volume of water in Container B, to the nearest tent of a cubic foot?
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Bonus Knowledge
To find the volume of water transferred to Container B from Container A, we first need to calculate the volume of each container using the formula for the volume of a cylinder, which is \( V = \pi r^2 h \). For Container A: - Diameter = 14 feet → Radius = 7 feet - Height = 15 feet \[ V_A = \pi (7)^2 (15) = \pi (49)(15) = 735\pi \text{ cubic feet} \approx 2304.6 \text{ cubic feet} \] For Container B: - Diameter = 18 feet → Radius = 9 feet - Height = 11 feet \[ V_B = \pi (9)^2 (11) = \pi (81)(11) = 891\pi \text{ cubic feet} \approx 2793.5 \text{ cubic feet} \] When we pump all the water from Container A into Container B, Container B will hold the entire volume of water from Container A: \[ V_B = 735\pi \approx 2304.6 \text{ cubic feet} \] Thus, to the nearest tenth, the volume of water in Container B after Container A is empty is approximately **2304.6 cubic feet**.