\( \rightleftarrows \) Get a similar question You can If \( \log _{2}(7 x+6)=1 \), then \( x= \) You may enter the exact value or round

To solve \( \log_{2}(7x + 6) = 1 \), we start by rewriting the logarithmic equation in exponential form. This means we can express it as \( 7x + 6 = 2^1 \). Simplifying this gives us \( 7x + 6 = 2 \). Now, subtract 6 from both sides to isolate the term with \( x \): \[ 7x = 2 - 6 \] \[ 7x = -4 \] Next, divide both sides by 7: \[ x = -\frac{4}{7} \] So the solution is \( x = -\frac{4}{7} \). For a similar question, try solving \( \log_{3}(x - 1) = 2 \). To solve it, express it in exponential form: \( x - 1 = 3^2 \), which simplifies to \( x - 1 = 9 \). Thus, \( x = 10 \).