$$ \rightleftarrows $$ Get a similar question You can If $$ \log _{2}(7 x+6)=1 $$, then $$ x= $$ You may enter the exact value or round

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Solve the equation $$ \log_{2}(7x+6)=1 $$.
Solve the equation by following steps:
- step0: Solve for $$x$$:
  $$\log_{2}{\left(7x+6\right)}=1$$
- step1: Find the domain:
  $$\log_{2}{\left(7x+6\right)}=1,x>-\frac{6}{7}$$
- step2: Convert the logarithm into exponential form:
  $$7x+6=2^{1}$$
- step3: Evaluate the power:
  $$7x+6=2$$
- step4: Move the constant to the right side:
  $$7x=2-6$$
- step5: Subtract the numbers:
  $$7x=-4$$
- step6: Divide both sides:
  $$\frac{7x}{7}=\frac{-4}{7}$$
- step7: Divide the numbers:
  $$x=-\frac{4}{7}$$
- step8: Check if the solution is in the defined range:
  $$x=-\frac{4}{7},x>-\frac{6}{7}$$
- step9: Find the intersection:
  $$x=-\frac{4}{7}$$
The solution to the equation $$ \log_{2}(7x+6)=1 $$ is $$ x = -\frac{4}{7} $$ or $$ x \approx -0.571428 $$.
$$ x = -\frac{4}{7} $$ or $$ x \approx -0.571428 $$

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