Question
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10. After pitching \( 6 \frac{3}{3} \) innings in his latest game, Barron has pitched more innings than his \( 82 \frac{1}{3} \) innings pitched tast season. How many innings, \( x \), might he have pitched before his latest game? Write an inequality to represent the situation. Solve your inequality.

Ask by Norris Wang. in the United States
Jan 22,2025

Real Tutor Solution

Tutor-Verified Answer

Answer

The inequality is \( x + 7 > 82 \frac{1}{3} \). Solving this gives \( x > 75 \frac{1}{3} \) innings pitched before the latest game.

Solution

Let's break down the problem step by step. ### **Understanding the Problem** - **Latest Game:** Barron pitched \( 6 \frac{3}{3} \) innings. - **Total After Latest Game:** This total should exceed his previous season's innings of \( 82 \frac{1}{3} \) innings. - **Goal:** Find the number of innings, \( x \), Barron might have pitched **before** his latest game. ### **Simplifying Mixed Numbers** First, simplify the mixed numbers to improper fractions or decimal form for easier calculation: - \( 6 \frac{3}{3} = 6 + 1 = 7 \) innings - \( 82 \frac{1}{3} = 82.333\ldots \) innings ### **Setting Up the Inequality** Let \( x \) represent the number of innings pitched **before** the latest game. After pitching 7 innings in the latest game, his total innings become: \[ x + 7 \] According to the problem, this total is **more than** \( 82 \frac{1}{3} \) innings: \[ x + 7 > 82 \frac{1}{3} \] ### **Solving the Inequality** Subtract 7 from both sides to isolate \( x \): \[ \begin{align*} x + 7 &> 82 \frac{1}{3} \\ x &> 82 \frac{1}{3} - 7 \\ x &> 75 \frac{1}{3} \end{align*} \] ### **Conclusion** Barron must have pitched **more than** \( 75 \frac{1}{3} \) innings before his latest game. ### **Final Answer** An inequality is x + 7 > 82 1⁄3. Solving gives x > 75 1⁄3 innings pitched before the latest game.

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The Deep Dive

Barron has pitched \( 6 \frac{3}{3} \) innings in his latest game, which simplifies to \( 7 \) innings. The total innings he has pitched can be represented as \( x + 7 > 82 \frac{1}{3} \). Converting \( 82 \frac{1}{3} \) to an improper fraction gives us \( 82.3333 \). This leads to the inequality: \( x + 7 > 82.3333 \). To solve for \( x \), we subtract \( 7 \) from both sides. This gives us \( x > 82.3333 - 7 \), which simplifies to \( x > 75.3333 \). Therefore, Barron must have pitched more than \( 75 \frac{1}{3} \) innings before today's game. So the final inequality is \( x > 75 \frac{1}{3} \). Now go pitch those innings, Barron!

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