10. After pitching \( 6 \frac{3}{3} \) innings in his latest game, Barron has pitched more innings than his \( 82 \frac{1}{3} \) innings pitched tast season. How many innings, \( x \), might he have pitched before his latest game? Write an inequality to represent the situation. Solve your inequality.
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Barron has pitched \( 6 \frac{3}{3} \) innings in his latest game, which simplifies to \( 7 \) innings. The total innings he has pitched can be represented as \( x + 7 > 82 \frac{1}{3} \). Converting \( 82 \frac{1}{3} \) to an improper fraction gives us \( 82.3333 \). This leads to the inequality: \( x + 7 > 82.3333 \). To solve for \( x \), we subtract \( 7 \) from both sides. This gives us \( x > 82.3333 - 7 \), which simplifies to \( x > 75.3333 \). Therefore, Barron must have pitched more than \( 75 \frac{1}{3} \) innings before today's game. So the final inequality is \( x > 75 \frac{1}{3} \). Now go pitch those innings, Barron!