Find $$ f(x)-g(x)=(f-g)(x) $$. Simplify. $$ \begin{aligned} f(x) & =7 x^{2}-5 x+7 \ g(x) & =11-x^{3}-2 x^{2} \ (f-g)(x) & =\end{aligned} $$

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1. Write the difference:
   $$
   (f-g)(x) = f(x) - g(x) = \left(7x^{2} - 5x + 7\right) - \left(11 - x^{3} - 2x^{2}\right)
   $$

2. Distribute the negative sign to the second group:
   $$
   (f-g)(x) = 7x^{2} - 5x + 7 - 11 + x^{3} + 2x^{2}
   $$

3. Rearrange and combine like terms:
   $$
   (f-g)(x) = x^{3} + \left(7x^{2} + 2x^{2}\right) - 5x + \left(7 - 11\right)
   $$
   $$
   (f-g)(x) = x^{3} + 9x^{2} - 5x - 4
   $$

Thus, the simplified result is:
$$
(f-g)(x) = x^{3} + 9x^{2} - 5x - 4
$$
$$ (f-g)(x) = x^{3} + 9x^{2} - 5x - 4 $$

Find . Simplify.

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