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\[ \text { Relation } 4 \] \[ \{(8, f),(-2, f),(1, f),(-6, f)\} \] Function Not a function

Ask by Ramos Summers. in the United States
Feb 02,2025

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The relation is a function.

Solution

To determine whether the given relation is a **function**, we need to verify that each input (the first element of each ordered pair) is associated with exactly one output (the second element of each ordered pair). **Given Relation:** \[ \{(8, f), (-2, f), (1, f), (-6, f)\} \] **Analysis:** - **Inputs:** 8, -2, 1, -6 - **Outputs:** All inputs are associated with the same output, \( f \). **Criteria for a Function:** - **Uniqueness:** Each input must be associated with exactly one output. - **Multiple outputs for a single input violate the function definition.** In this relation: - Each input has exactly one corresponding output. - Even though multiple inputs share the same output (\( f \)), this does **not** violate the definition of a function. A function can have different inputs mapping to the same output. **Conclusion:** The given relation satisfies the criteria for a function. **Answer:** Function

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The Deep Dive

The relation you've provided includes pairs of the form \((x, f)\) where the same first component \(x\) appears with the same second component \(f\). However, if any \(x\) value were to map to more than one \(f\) value, then it wouldn't be considered a function. In the given relation, each \(x\) value is unique, suggesting that it could indeed be a function if all the pairs were to map correctly without any duplication. One common mistake when determining if a relation is a function is overlooking the uniqueness of \(x\) values. It's crucial to check if for every input \(x\), there is exactly one output. An easy way to visualize this is to think about a vending machine: for each button you press (input), you only want one snack (output) to drop down. If pressing one button gives you different snacks, that’s a problem! Always ensure inputs have consistent outputs!

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