2 Directions - Solve the proportion for \( \mathbf{y} \) : \( \frac{8}{2 y-3}=\frac{6}{y+4} \) \( y=\square \)
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To solve the proportion \( \frac{8}{2y-3}=\frac{6}{y+4} \), you can use cross-multiplication. This means multiplying the numerator of one fraction by the denominator of the other fraction. So, we get: \[ 8(y + 4) = 6(2y - 3) \] Expanding both sides, you will find: \[ 8y + 32 = 12y - 18 \] Now, rearranging the equation to isolate \( y \) gives us: \[ 32 + 18 = 12y - 8y \] This simplifies to: \[ 50 = 4y \] Dividing by 4: \[ y = \frac{50}{4} = 12.5 \] So, \( y = 12.5 \). To check, substitute \( y \) back into the original fractions to ensure they are equal! How neat is that?