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Find the indicated probability using the standard normal distribution. \( P(-1.86
Ask by Elliott Fuentes. in the United States
Feb 03,2025

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Answer

The probability \( P(-1.86 < z < 0) \) is 0.4686.

Solution

To find the probability \( P(-1.86 < z < 0) \) using the standard normal distribution, we can break it down into two parts: 1. Find \( P(z < 0) \) 2. Find \( P(z < -1.86) \) 3. Subtract the second probability from the first to get \( P(-1.86 < z < 0) \). ### Step 1: Find \( P(z < 0) \) The standard normal distribution is symmetric around zero. Therefore, the probability that \( z \) is less than 0 is: \[ P(z < 0) = 0.5 \] ### Step 2: Find \( P(z < -1.86) \) Next, we need to look up the value of \( P(z < -1.86) \) in the standard normal table. From the standard normal table, we find: \[ P(z < -1.86) \approx 0.0314 \] ### Step 3: Calculate \( P(-1.86 < z < 0) \) Now we can calculate the probability: \[ P(-1.86 < z < 0) = P(z < 0) - P(z < -1.86) \] Substituting the values we found: \[ P(-1.86 < z < 0) = 0.5 - 0.0314 = 0.4686 \] ### Final Answer Thus, the probability \( P(-1.86 < z < 0) \) rounded to four decimal places is: \[ \boxed{0.4686} \]

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