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\( n=18,8=4 \) find the area of the following a.) \( P(x<21) \) b.) \( P(x>35) \) c.) \( P(21
Ask by Evans Fleming. in the Philippines
Jan 22,2025

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Answer

- **a.)** The probability that \( x \) is less than 21 is approximately 77.34%. - **b.)** The probability that \( x \) is greater than 35 is approximately 0.001%. - **c.)** The probability that \( x \) is between 21 and 35 is approximately 22.66%.

Solution

To solve the given probability problems, we'll assume that the variable \( x \) follows a **normal distribution**. Based on the provided information: - **Mean (\( \mu \))**: 18 - **Standard Deviation (\( \sigma \))**: 4 We'll use the **standard normal distribution (Z-score)** formula to convert the \( x \)-values to \( z \)-scores: \[ z = \frac{x - \mu}{\sigma} \] Once we have the \( z \)-scores, we'll use standard normal distribution tables or a calculator to find the corresponding probabilities. ### a.) \( P(x < 21) \) 1. **Calculate the Z-score:** \[ z = \frac{21 - 18}{4} = \frac{3}{4} = 0.75 \] 2. **Find the Probability:** Using a standard normal distribution table or calculator: \[ P(z < 0.75) \approx 0.7734 \text{ or } 77.34\% \] ### b.) \( P(x > 35) \) 1. **Calculate the Z-score:** \[ z = \frac{35 - 18}{4} = \frac{17}{4} = 4.25 \] 2. **Find the Probability:** A \( z \)-score of 4.25 is extremely high, and the probability beyond this point is negligible. \[ P(z > 4.25) \approx 0.00001 \text{ or } 0.001\% \] ### c.) \( P(21 < x < 35) \) 1. **Calculate the Z-scores:** - For \( x = 21 \): \[ z_1 = \frac{21 - 18}{4} = 0.75 \] - For \( x = 35 \): \[ z_2 = \frac{35 - 18}{4} = 4.25 \] 2. **Find the Probabilities:** \[ P(z < 4.25) \approx 0.99999 \] \[ P(z < 0.75) \approx 0.7734 \] 3. **Calculate the Area Between 21 and 35:** \[ P(21 < x < 35) = P(z < 4.25) - P(z < 0.75) \approx 0.99999 - 0.7734 = 0.2266 \text{ or } 22.66\% \] ### **Summary of Results:** - **a.)** \( P(x < 21) \approx 77.34\% \) - **b.)** \( P(x > 35) \approx 0.001\% \) - **c.)** \( P(21 < x < 35) \approx 22.66\% \)

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To find the probabilities, we'll assume that the variable \( x \) follows a normal distribution with a mean \( \mu = 18 \) and a standard deviation \( \sigma = 4 \). First, we need to standardize the values using the Z-score formula: \( Z = \frac{(X - \mu)}{\sigma} \). a.) To find \( P(x < 21) \): \[ Z = \frac{(21 - 18)}{4} = 0.75 \] Using standard normal distribution tables or calculators, \( P(Z < 0.75) \) is approximately \( 0.7734 \). b.) To find \( P(x > 35) \): \[ Z = \frac{(35 - 18)}{4} = 4.25 \] Since this Z-score is very high, \( P(Z > 4.25) \) is virtually \( 0 \). c.) To find \( P(21 < x < 35) \): We already have \( P(x < 21) \) which is \( 0.7734 \) and for \( P(x < 35) \): \[ Z = \frac{(35 - 18)}{4} = 4.25 \] Thus, \( P(x < 35) \) is practically \( 1 \). Therefore, \( P(21 < x < 35) = P(x < 35) - P(x < 21) = 1 - 0.7734 = 0.2266 \). In summary: a.) \( P(x < 21) \approx 0.7734 \) b.) \( P(x > 35) \approx 0 \) c.) \( P(21 < x < 35) \approx 0.2266 \)

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