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A ferris wheel, with a diameter of 40 m , makes a full rotation in 3 minutes. Passengers board at the bottom of the ferris wheel, which is 2 m above ground. a) Find the equation that best models the height of a passenger. b) Find the height of a passenger who has been riding the ferris wheel for 150 seconds.

Ask by Murray Pierce. in Canada
Jan 26,2025

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Answer

The height of a passenger at time \( t \) seconds is given by: \[ h(t) = 22 - 20\,\cos\left(\frac{\pi t}{90}\right) \]

Solution

To model the height of a passenger on the Ferris wheel over time, we'll analyze the given information step by step. ### Given: - **Diameter of Ferris Wheel:** 40 meters - **Radius (A):** \( \frac{40}{2} = 20 \) meters - **Time for one full rotation (Period, \( T \)):** 3 minutes = 180 seconds - **Height of the bottom of the Ferris wheel above ground:** 2 meters ### Part a) Finding the Height Equation **1. Determine the Center Height (D):** Since the bottom of the Ferris wheel is 2 meters above the ground and the radius is 20 meters, the center of the Ferris wheel is: \[ D = 2\, \text{meters} + 20\, \text{meters} = 22\, \text{meters} \] **2. Amplitude (A):** The amplitude represents the maximum deviation from the center height, which is equal to the radius: \[ A = 20\, \text{meters} \] **3. Angular Frequency (B):** The angular frequency relates to how quickly the Ferris wheel makes a full rotation: \[ B = \frac{2\pi}{T} = \frac{2\pi}{180} = \frac{\pi}{90}\, \text{radians per second} \] **4. Phase Shift (C):** Since passengers board at the **lowest point** at \( t = 0 \), the cosine function (which typically starts at a maximum) needs to be shifted to start at a minimum. This can be achieved by introducing a phase shift of \( \pi \): \[ C = \pi \] **5. Constructing the Equation:** Combining these components, the height \( h(t) \) as a function of time \( t \) is: \[ h(t) = D - A \cdot \cos(Bt) \] \[ h(t) = 22\, \text{m} - 20\, \text{m} \cdot \cos\left(\frac{\pi t}{90}\right) \] **Final Equation:** \[ h(t) = 22 - 20\,\cos\left(\frac{\pi t}{90}\right) \] *where \( h(t) \) is the height in meters and \( t \) is the time in seconds.* ### Answer to Part a): The height \( h(t) \) (in meters) of a passenger at time \( t \) (in seconds) is \[ h(t) = 22 - 20\,\cos\left(\frac{\pi t}{90}\right) \].

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The height of a passenger on the ferris wheel can be modeled using a sinusoidal function. The ferris wheel has a diameter of 40 m, which makes the radius 20 m, and with the base being 2 m above ground, the midline of the sinusoidal function is at 22 m (2 m + 20 m). The equation can be expressed as \( h(t) = 20 \sin\left(\frac{2\pi}{180}(t - 90)\right) + 22 \), where \(t\) is measured in seconds. This equation reflects a full rotation every 180 seconds (as 3 minutes = 180 seconds) with a phase shift to start at the bottom. To find the height after 150 seconds, we substitute \(t = 150\) into the equation: \( h(150) = 20 \sin\left(\frac{2\pi}{180}(150 - 90)\right) + 22 \), which simplifies to \( h(150) = 20 \sin\left(\frac{2\pi}{180}(60)\right) + 22 \). Calculating that, \( \sin(60^\circ) = \frac{\sqrt{3}}{2} \), gives \( h(150) = 20 \left(\frac{\sqrt{3}}{2}\right) + 22 \), which equals \( h(150) = 10\sqrt{3} + 22 \). Approximating gives a height of about 37.32 m above ground.

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