A ferris wheel, with a diameter of 40 m , makes a full rotation in 3 minutes. Passengers board at the bottom of the ferris wheel, which is 2 m above ground. a) Find the equation that best models the height of a passenger. b) Find the height of a passenger who has been riding the ferris wheel for 150 seconds.
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The height of a passenger on the ferris wheel can be modeled using a sinusoidal function. The ferris wheel has a diameter of 40 m, which makes the radius 20 m, and with the base being 2 m above ground, the midline of the sinusoidal function is at 22 m (2 m + 20 m). The equation can be expressed as \( h(t) = 20 \sin\left(\frac{2\pi}{180}(t - 90)\right) + 22 \), where \(t\) is measured in seconds. This equation reflects a full rotation every 180 seconds (as 3 minutes = 180 seconds) with a phase shift to start at the bottom. To find the height after 150 seconds, we substitute \(t = 150\) into the equation: \( h(150) = 20 \sin\left(\frac{2\pi}{180}(150 - 90)\right) + 22 \), which simplifies to \( h(150) = 20 \sin\left(\frac{2\pi}{180}(60)\right) + 22 \). Calculating that, \( \sin(60^\circ) = \frac{\sqrt{3}}{2} \), gives \( h(150) = 20 \left(\frac{\sqrt{3}}{2}\right) + 22 \), which equals \( h(150) = 10\sqrt{3} + 22 \). Approximating gives a height of about 37.32 m above ground.