Solve the system by substitution. \[ \begin{aligned} y & =5 x+30 \\ y & =2 x\end{aligned} \]
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To solve the system by substitution, we can set the two equations equal to each other since they both equal \(y\): Given: 1. \(y = 5x + 30\) 2. \(y = 2x\) We can equate them: \[ 5x + 30 = 2x \] Now, let's isolate \(x\): \[ 5x - 2x = -30 \] \[ 3x = -30 \] \[ x = -10 \] Now substitute \(x = -10\) back into either equation to find \(y\). We'll use the second equation: \[ y = 2(-10) \] \[ y = -20 \] Thus, the solution to the system of equations is: \[ (x, y) = (-10, -20) \]