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Which of the following is equivalent to \( i^{8} \) ?

Ask by Grant Knight. in the United States
Nov 25,2024

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Answer

The equivalent of \( i^8 \) is 1.

Solution

To find \( i^8 \), we start by recalling the powers of the imaginary unit \( i \), where \( i = \sqrt{-1} \). The powers of \( i \) cycle every four terms: \[ \begin{align*} i^1 & = i, \\ i^2 & = -1, \\ i^3 & = -i, \\ i^4 & = 1. \end{align*} \] After \( i^4 \), the pattern repeats: \[ \begin{align*} i^5 & = i, \\ i^6 & = -1, \\ i^7 & = -i, \\ i^8 & = 1. \end{align*} \] To compute \( i^8 \), we can also use the fact that the powers of \( i \) repeat every four terms. We can find the equivalent power by calculating \( 8 \mod 4 \): \[ 8 \div 4 = 2 \quad \text{(remainder 0)}. \] Since the remainder is 0, we have: \[ i^8 = i^0 = 1. \] Thus, the equivalent of \( i^8 \) is \[ \boxed{1}. \]

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To find \( i^{8} \), we can look at the powers of \( i \) and see that they follow a cyclical pattern: \( i^1 = i \), \( i^2 = -1 \), \( i^3 = -i \), and \( i^4 = 1 \). These powers repeat every four terms, so we can simplify \( i^{8} \) as follows: Since \( 8 \div 4 = 2 \) with a remainder of \( 0 \), we find that \( i^{8} = (i^4)^{2} = 1^{2} = 1 \). So, \( i^{8} \) is equivalent to \( 1 \).

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