aiculate the value of the expression \( 3 x^{2}+4 x-5 \) when \( \begin{array}{lll}x=-1 & \text { b) } x=-2 & \text { c) } x=0\end{array} \) he temperature in Moscow was \( 2^{\circ} \mathrm{C} \). Then it dropped to \( 8^{\circ} \mathrm{C} \) below zero. By om thany degrees did the temperature drop?
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To evaluate the expression \( 3x^2 + 4x - 5 \) for the given values of \( x \): When \( x = -1 \): \( 3(-1)^2 + 4(-1) - 5 = 3(1) - 4 - 5 = 3 - 4 - 5 = -6 \). When \( x = -2 \): \( 3(-2)^2 + 4(-2) - 5 = 3(4) - 8 - 5 = 12 - 8 - 5 = -1 \). When \( x = 0 \): \( 3(0)^2 + 4(0) - 5 = -5 \). As for the temperature, it dropped from \( 2^{\circ} \mathrm{C} \) to \( 8^{\circ} \mathrm{C} \) below zero, which is equivalent to \( -8^{\circ} \mathrm{C} \). To determine the drop: \( 2 - (-8) = 2 + 8 = 10^{\circ} \mathrm{C} \). So, the temperature dropped by \( 10^{\circ} \mathrm{C} \).