Question
Find the domain of the function. \( g(x)=\frac{x+7}{x^{2}-16} \) The domain is \( \square \). (Type your answer in interval notation.)
Ask by Erickson Hilton. in the United States
Jan 23,2025
Real Tutor Solution
Tutor-Verified Answer
Answer
The domain is \( (-\infty, -4) \cup (-4, 4) \cup (4, \infty) \).
Solution
To determine the **domain** of the function \( g(x) = \frac{x+7}{x^{2}-16} \), we need to identify all real numbers \( x \) for which the function is defined.
The function \( g(x) \) is a **rational function**, which means it is defined for all real numbers **except** those that make the **denominator** equal to zero (since division by zero is undefined).
1. **Set the denominator equal to zero and solve for \( x \):**
\[
x^{2} - 16 = 0
\]
\[
x^{2} = 16
\]
\[
x = \pm 4
\]
2. **Exclude these values from the domain:**
The function is undefined at \( x = 4 \) and \( x = -4 \).
3. **Express the domain in interval notation:**
\[
(-\infty, -4) \cup (-4, 4) \cup (4, \infty)
\]
**Final Answer:**
The domain is \( (-\infty, -4) \cup (-4, 4) \cup (4, \infty) \).
Reviewed and approved by the UpStudy tutoring team
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The Deep Dive
To find the domain of \( g(x)=\frac{x+7}{x^{2}-16} \), we need to set the denominator not equal to zero. The denominator is \( x^2 - 16 = 0 \), which can be factored as \( (x - 4)(x + 4) = 0 \). This gives us the solutions \( x = 4 \) and \( x = -4 \). Thus, the function is undefined at these points. The domain of \( g(x) \) is all real numbers except \( -4 \) and \( 4 \), which in interval notation can be expressed as \( (-\infty, -4) \cup (-4, 4) \cup (4, \infty) \). The domain is \( (-\infty, -4) \cup (-4, 4) \cup (4, \infty) \).