An order of coffee and sugar weighs 10 pounds and costs \( \$ 14 \). Coffee: \( \$ 2.00 \) per pound Sugar: \( \$ 0.50 \) per pound How many pounds of coffee and sugar are in this order? Ho you need to set the expression equal to? Reread the problem to determine the total cost of the order.

To tackle this problem, you can set up a system of equations. Let \( c \) represent the pounds of coffee and \( s \) represent the pounds of sugar. You have two main equations based on the information given: 1. \( c + s = 10 \) (the total weight is 10 pounds) 2. \( 2c + 0.5s = 14 \) (the total cost is $14) These equations will guide you towards finding the values of \( c \) and \( s \)! A common mistake when solving these types of problems is to misinterpret the costs or to forget to apply the constraints from both equations. Ensure that you carefully define your variables, isolate one variable when needed, and double-check your calculations. What's fun is that once you find \( c \) and \( s \), you’ll have some smooth coffee vibes and sweet sugar added to your day!