QUESTION 7 Two trig functions namely, \( f(x)=a \cos x \) and \( g(x)=\sin b x \), are shown below for \( x \in\left[-180^{\circ} ; 180^{\circ}\right] \). 7.1 Determine; 7.1 .1 the value of \( a \) and \( b \). 713 the range of \( f \).
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When dealing with the functions \( f(x) = a \cos x \) and \( g(x) = \sin b x \), we know that the cosine function oscillates between -1 and 1. Therefore, the amplitude \( a \) will determine how "tall" the peaks and "deep" the valleys of the cosine curve extend. If the maximum value of \( f(x) \) is \( a \) and the minimum is \( -a \), you can calculate the value of \( a \) based on the maximum height of \( f(x) \) observed in the graph. For the sine function to match the oscillatory characteristics of the cosine function within the specified interval, \( b \) is derived from how frequently \( g(x) \) oscillates within that interval. If \( g(x) \) is not deviating from typical sine behavior (with a frequency coefficient of 1), then \( b \) typically equals 1. But if the sine function completes multiple cycles within the range of \( x \), then you'd have to reflect that in the calculation of \( b \). The range of \( f \) is straightforward: it extends from its minimum value of \( -a \) to its maximum of \( a \). So the range of \( f(x) = a \cos x \) would be in the form \([-a, a]\).